Tentukan nilai k sehingga suku banyak 4x³-x²+kx+2½ habis dibagi (2x+3)

jawab

f(x)  = 4x³ - x² + kx + 5/2
habis dibagi (2x +3)
2x +3= 0
x = - 3/2

f(3/2) = 0
4(-3/2)³ - (-3/2)²+ k(-3/2) + 5/2  = 0
4(-27/8) - 9/4  - 3/2 k + 5/2 = 0 
-108/8 - 9/4 - 3/2 k + 5/2 = 0 } kali 8
-108 - 18 - 12k + 20 =0
-12 k - 106 = 0
-12 k = 106
k = - 106/12 = - 8⁵/₆