tolong jawab ya kak pakai cara nya

jawab

y = 1/x² - √x
titkk absis 1 → x = 1 maka  y = (1/1) - √1 = 0
titk (x,y)= (1,0)

y = 1/x² - √x
y = x⁻² - x^(1/2)
m= y' = -2 x⁻³ - 1/2 x^(-1/2)
m= -2/x³ - 1/(2√x)
x= 1 , m= -2/(1)³ - 1/(2√1)
m = -2 - 1/2
m = - 5/2

persamaan garis m= - 5/2 melalui titik (x1,y1)= (1,0)
y - y1 = m ( x - x1)
y - 0 = - 5/2 (x -1)
2(y-0) = -5(x - 1)
2y = - 5x + 5
5x + 2y = 5
5x + 2y - 5 = 0