2x-5y+6z=13 -3x+2y+4z=29 5x+3y-2z=-6
Matematika
atika174
Pertanyaan
2x-5y+6z=13 -3x+2y+4z=29 5x+3y-2z=-6
1 Jawaban
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1. Jawaban ahreumlim
2x - 5y + 6z = 13 ................(1)
-3x + 2y + 4z = 29 ..............(2)
5x + 3y - 2z = -6 .................(3)
dari (2) dan (3)
-3x + 2y + 4z = 29 |x1| -3x + 2y + 4z = 29
5x + 3y - 2z = -6 |x2| 10x + 6y - 4z = -12
-3x + 2y + 4z = 29
10x + 6y - 4z = -12 +
-------------------------------
7x + 8y = 17 ....................(4)
dari (1) dan (3)
2x - 5y + 6z = 13 |x1| 2x - 5y + 6z = 13
5x + 3y - 2z = -6 |x3| 15x + 9y - 6z = -18
2x - 5y + 6z = 13
15x + 9y - 6z = -18 +
------------------------------
17x + 4y = -5 ....................(5)
dari (4) dan (5)
7x + 8y = 17 |x1| 7x + 8y = 17
17x + 4y = -5 |x2| 34x + 8y = -10
7x + 8y = 17
34x + 8y = -10 -
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27x = -27
x = -1
subtitusikan x = -1 ke pers. (4)
7x + 8y = 17
7(-1) + 8y = 17
-7 + 8y = 17
8y = 17 + 7
8y = 24
y = 3
subtitusikan nilai x = -1 dan y = 3 ke pers. (3)
5x + 3y - 2z = -6
5(-1) + 3(3) - 2z = -6
-5 + 9 - 2z = -6
2z = -5 + 9 + 6
2z = 10
z = 5
Jadi solusinya adalah
x = -1
y = 3
z = 5
HP : {(-1,3,5)}