tolong ya no 1 , 2 , 3 no 1 dulu deh makasih ya

1) a)garis pelukis=√t²+r²
=√2²+1,5²
=√4+2,25
=√6,25
=2,5 cm

b)maaf gk di isi

2)a)garis pelukis=√t²+r²
=√24²+7²
=√576+49
=√625
=25 cm

b)selimut kerucut=π×r×s
=22/7×7×25
=3850/7
=550 cm²

3)a)luas selimut=π×r×s
471=3,14×r×25
471=78,5r
r=471/78,5
r=6 cm

b)luas kerucut=π×r(r+s)
=3,14×6(6+25)
=18,84(31)
=584,04 cm²