2log 7= a 2log 3 = b 6 log 14=?

²log7 = a
²log3 = b

⁶log14
= (²log14) / (²log6)
= [²log(2 x 7)] / [²log(2 x 3)]
= (²log2 + ²log7) / (²log2 + ²log3)
= (1 + a) /(1 + b)