Matematika

Pertanyaan

tolong pengting no 4
tolong pengting no 4

2 Jawaban

  • Luas selimut = 942 cm²
    D = 20 cm
    r = D/2 = 20 / 2 = 10 cm

    Luas selimut = 942
    2.π.r.t = 942
    2 x 3,14 x 10 x t = 942
    62,8 x t = 942
    t = 942 / 62,8
    t = 15 cm

    jawaban C
  • selimut= keliling × tinggi
    942= (π× 20) × tinggi
    942= (3,14×20) × t
    942 = 62,8×t
    942÷62,8 = t
    15 = t
    tinggi = 15