Matematika

Pertanyaan

PR MTK BAB 3 KELAS 5 SD

3hm =............dam
2m+3dam =............cm
4kc =........... c
3kc+7he =...........dac
14c =.............dam

1 Jawaban

  • 3hm = 3×10=30dam
    2m×100=200cm+3dam×10=30cm.200+30=230cm
    4kc×1000=4000c
    3×100=300dac+7×100=700.300+700=1.000 dac
    14×10=140dam

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