kak tolong dong kak integral

jawab

₀¹∫ x√(x² +9) dx

u = x²  +9
du = 2x dx
x dx = 1/2 du

batas integral
u  = x² + 9
x =0 , u = 9
x = 1 , u = 10

₉¹⁰∫ 1/2 u^(1/2) du =
= [1/2 (2/3) U^(3/2) ]¹⁰₉
= 1/3 [u √u ]¹⁰₉
= 1/3 (10√10 - 9√9)
= 1/3 (10√10 - 27)