caranya gmana ya kak

Diket: x1(4/3,0) x2(-2,0) y(0,-8)

Jawab:
y = a(x-x1)(x-x2)
-8 = a(0-4/3)(0+2)
-8 = a (-4/3) (2)
-8 = -8/3a
-8.3 = -8a
-24 = -8a
a = -24/-8
a = 3

Kembali ke rumus I
y = a(x-x1)(x-x2)
y = 3(x-4/3)(x+2)
y = 3 (x² + 2x - 4/3x - 8/3 )
y = 3 (x² + 2/3x - 8/3)
y = 3x² + 2x - 8

Semoga bermanfaat!
Jadikan jawaban terbaik ya :D