Matematika

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Nilai dari ²log3 + ²log8 - ²log6 adalah...

1 Jawaban

  • ²log3 + ²log8 - ²log6 = ²log(3 x 8 : 6)
                                    = ²log4
                                    = ²log2²
                                    = 2 x ²log2
                                    = 2 x 1
                                    = 2

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