1/x + 1/y = 10 dan 5/x - 3/y = 6 tentukan nilai x yang memenuhi sistem persamaaan adalah

1/x + 1/y = 10

y + x / (xy) = 10

5/x - 3/y = 6
5y - 3x / xy = 6
-3x + 5y = 6xy

Eliminasi
x + y / xy = 10 (x5)
- 3xy + 5y / xy = 6


5x + 5y /xy = 50
-3x + 5y / xy = 6
>> 8x / xy = 44
y = 8/44


x + y / xy = 10
x + 8/44 / 8/ 44 = 10
x + 8/44 = 20/11
>> x = 80-8/44
= 72/4
= 13

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