persamaan hiperbola dengan puncak (3,4) dan melalui titik (1,1)

a = 3
b = 4
c = √4² + 3²
c = √16 + 9
c = √25
c = 5

titik fokus = c
c = p + a
5 = p + 3
p = 2

(x - 2)²/9 - (y - 4)²/16 = 1
16(x - 2)² - 9(y - 4)² = 144

garis singgung hiperbola melalui titik (1,1)
16(x - 2)(x1 - 2) - 9(y - 4)(y1 - 4) = 144
16(x - 2)(1 - 2) - 9(y - 4)(1 - 4) = 144
16(x - 2)(-1) - 9(y - 4)(-3) = 144
-16(x - 2) + 27(y - 4) = 144
-16x + 32 + 27y - 108 = 144
-16x + 27y = 144 + 108 - 32
-16x + 27y = 220