i. x + 3y + 2z = 16 ii. 2x + 4y - 2z = 12 iii. x + y + 4z = 20 substitusi kan
Matematika
fany95
Pertanyaan
i. x + 3y + 2z = 16
ii. 2x + 4y - 2z = 12
iii. x + y + 4z = 20
substitusi kan
ii. 2x + 4y - 2z = 12
iii. x + y + 4z = 20
substitusi kan
1 Jawaban
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1. Jawaban deeyach08oxpt6w
x + 3y + 2z = 16
2x + 4y - 2z = 12
x + y + 4z = 20
→→→→→→→→ +
4x + 8y+4z = 48