Jika nilai dari integral 1 dengan batas -1 x² (x-3)dx=m maka tentukan nilai m

jawab

₋₁¹∫ x²(x-3) dx = m
m = ₋₁¹∫ x³ - 3x²dx
m= [ 1/4 x⁴ - x³]¹₋₁
m = 1/4(0) - (2)
m = - 2

InTegraL

∫x²(x - 3) dx [1...-1]
= ∫(x³ - 3x²) dx
= 1/4 x⁴ - x³

(1/4 . 1⁴ - 1³) - (1/4 (-1)⁴ - (-1)³) = m
(1/4 - 1) - (1/4 + 1) = m
m = 0 - 2
m = -2 ✔