Amiya, Huiling and janice have 328 stickers altogether. Amiya has twice as many stickers as huiling. Janice has 58 more stickers than Amiya. How many stickers d

amiya = x
Huling = y
janice = z

maka , x+y+z=328
amiya memiliki 2*y
dan janice memiliki 58+x= 58+2*y
 sehingga,
2y+y+58+2y=328
6y=328-58
6y=270
y=45

jadi huiling mempunyai 45 stiker, shingga amiya memiliki 2*45=90