tentukan hasil penyelesaian dari sistem persamaan x+y+z= -6 x-2y+z=3 -2x+y+z=9 dengan metode eleminasi

x + y + z = - 6
x - 2y + z = 3
---------------------(-)
- y = = (- 9)
y = 9 ... pers 1

x - 2y + z = 3
-2x + y + z = 9
----------------------(-)
3x - 3y = - 6 ... pers 2

pers 1 & 2
3x - 3y = - 6
3x - 3(9) = - 6
3x - 27 = - 6
3x = - 6 + 27
3x = 21
x = 7

x + y + z = - 6
7 + 9 + z = - 6
z = - 6 - 16
z = - 22

Mapel : Matematika

Jawaban:

[tex] x + y + z = - 6 \\ x - 2y + z = 3 \\.......................... - \\ 3y = - 9 \\ y = - 3 \\\\ x + y + z = - 6\\-2x + y + z = 9 \\.......................... - \\ 3x = - 15 \\ x = - 5 [/tex]

Substitusi [tex] x=-5 [/tex] dan [tex] y = - 3 [/tex] ke salah satu persamaan

[tex] x + y + z = - 6 \\ - 5 + (-3) + z = - 6 \\ z = - 6 + 8 \\ z = 2 [/tex]

HP = {[tex] x, y, z[/tex]}
HP = {[tex] - 5, - 3, 2[/tex]}

Semoga membantu...