Jika fungsi f dan g adalah: f: x->2x^2/3 dan g: x->x^3/2 maka (gof)^-1 (akar2) adalah, tlong bantu saya plis.....

f(x) = 2x^(2/3)
y = 2x^2/3
x^2/3 = y/2
x = (y/2)^3/2

f^-1 (x) = (x/2)^(3/2)
••
g(x) = x^(3/2)
y = x^3/2
x = y^2/3

g^-1 (x) = x^2/3

••
(gof)^-1 (x)
= f^-1 o g^-1
= (x^2/3 /2)^3/2
= x/2^3/2

(gof)^-1 (√2)
= √2 / 2^3/2
= 2^(1/2 - 3/2)
= 2^-1
= 1/2 ✔