Matematika

Pertanyaan

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1 Jawaban

  • jawab

    (1)
    cos 72 + sin72 tan 36  = 1
    cos 72 + sin 72 tan 36 =
    = cos 72 + sin 72 . sin 36/cos 36
    = (cos 72 cos 36 + sin 72 sin 36)/cos 36
    = cos (72 - 36) / cos 36
    = cos 36/cos 36
    = 1

    (2)
    m =  p tan α
    n = p tan 2α
    n = 2p tan α/(1 - tan² α)

    (2m/n ) = 2 p tan α (1- tan² α)/(2p tan α)
    (2m/n ) = 1 - tan² α

    (2m/n- 1) p² +m² = 0
    (2m/n -1) p²  + m² =
    = (1 - tan² α - 1) p² + (p tan α) ²
    = - p² tan² α + p² tan² α
    = 0