selesaikan persamaan linier berikut (1.)5a=6+4a (2.)2n=n-5 (3.)-5p=2p-42
Matematika
munthofiah
Pertanyaan
selesaikan persamaan linier berikut (1.)5a=6+4a (2.)2n=n-5 (3.)-5p=2p-42
2 Jawaban
-
1. Jawaban shintafio
1. 5a = 6+4a
5a-4a=6
a=6
2. 2n = n-5
2n-n=-5
n=-5
3.-5p=2p-42
-5p-2p = -42
-7p = -42
p= -42/7
p=-6
semoga membantu -
2. Jawaban Soviyas
(1.) 5a = 6 + 4a
5a-4a = 6
a = 6
(2.) 2n=n-5
2n-n= -5
n = -5
(3.) -5p=2p-42
-5p-2p=42
-7p=42
p=42/-7
p= -6