1.) 333°k=......°f 2.) 330°k=.....°r 3.) 50°r=.....°f Beserta caranya

1. 333°K = 9/5 (°K - 273) + 32 = 9/5 (333°K - 273) + 32 = 9/5 (60) + 32 = 108 + 32 = 140°F

2. 330°K = 4/5 (°K - 273) = 4/5 (330°K - 273) = 273 - (4 × 60) = 273 - 240 = 33°R

3. 50°R = 9/4 (°R + 32) = 9/4 (50°R + 32) = (9 × 50) + 8 = 450 + 8 = 458°F

1.f= (9/5)(333-273)+32
=9/5×60+32
=9×12+32
=140.

2.r=4/5(330-273)+32
=4/5×57+32
=45.6+32
=77.6

3.f=(9/4)50+32
=9×50+8
=450+8
=458


maaf klo salah