Jika x1 dan x2 adalah akar akar persamaan kuadratnya ײ + 5× + 6 = 0,tentukan nilai : a.x1² + x2² b.(x1 - x2)² c.1/x1 + 1/x2 d.x1/x2 + x2/x1

ײ + 5× + 6 = 0
(X+3)(x+2)=0
X+3=0
X1=-3

X+2=0
x2=-2

a.x1² + x2² = (-3)² + (-2)² = 9+4=13

b.(x1 - x2)² = (-3-(-2))² =(-3+2)² =(-1)²=1

c.1/x1 + 1/x2 = 1/-3 + 1/-2 = -2/6 + -3/6 = -5/6

d.x1/x2 + x2/x1 = -3/-2 + -2/-3 = 9/6 + 4/6 = 13/6

Maaf kalo salah