Matematika

Pertanyaan

6log ( x^2 - 6x + 8) = 6log 24

1 Jawaban

  • Bab Logaritma
    Matematika SMA Kelas X

    ⁶log (x² - 6x + 8) = ⁶log 24
    x² - 6x + 8 = 24
    x² - 6x + 8 - 24 = 0
    x² - 6x - 16 = 0
    (x - 8) (x + 2) = 0
    x - 8 = 0
    x = 8

    x + 2 = 0
    x = -2

    syarat
    x² - 6x + 8 > 0
    (x - 4) (x - 2) > 0
    x - 2 < 0
    x < 2

    x - 4 > 0
    x > 4

    HP = { -2, 8 }

     


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