3log2x + 3logx - 6 = 0

3log(2x×x) -6 =0

3log(2x^2) = 6

(2x^2)=3^6

x^2 = (3^6)/2
x = akar((3^6)/2)

x = 3^3 akar(1/2)

x = (27/2)×akar(2)

³㏒²x+³㏒x-6=0
misal : ³㏒x=y
y²+y-6=0
(y-2)(y+3)=0
y=2 atau y=-3

y=2
³㏒x=2
3²=x
x=9

y=-3
³㏒x=-3
3^-3=x
x=1/27